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-.06x^2+69x+325=0
We add all the numbers together, and all the variables
-0.06x^2+69x+325=0
a = -0.06; b = 69; c = +325;
Δ = b2-4ac
Δ = 692-4·(-0.06)·325
Δ = 4839
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-\sqrt{4839}}{2*-0.06}=\frac{-69-\sqrt{4839}}{-0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+\sqrt{4839}}{2*-0.06}=\frac{-69+\sqrt{4839}}{-0.12} $
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